# Time Sequence Test

**Important Points: -**

- A year has 365 days.
- Years, divisible by 4, are leap years e.g., 1980, 1984, 1988, 1992, 1996, .…. They have 366 days.
- February in a leap year has 29 days.
- The last day of a year is the same as first day.

Thus, if the first day of a year is Monday, then the last day of that year is also Monday and the first day of the next year is Tuesday.

However, if the first day of a leap year is Monday, then the last day of that year is Tuesday and the first day of the next year is Wednesday.

** Example:** Kailash remembers that his brother Deepak’s birthday falls after 20

^{th}May but before 28

^{th}May, while Geeta remember that Deepak’s birthday falls before 22

^{nd}May but after 12

^{th}May. On what date Deepak’s birthday falls?

- 20
^{th}May - 21
^{st}May - 22
^{nd}May - Cannot be determined
- None of these

** Answer:** According to Kailash, Deepak’s birthday falls on one of the days among 21

^{st}, 22

^{nd}, 23

^{rd}, 24

^{th}, 25

^{th}, 26

^{th}and 27

^{th}May.

According to Geeta, Deepak’s birthday falls on one of the days among 13^{th}, 14^{th}, 15^{th}, 16^{th}, 17^{th}, 18^{th}, 19^{th}, 20^{th} and 21^{st} May.

The day common to both the groups is 21^{st} May.

\ Deepak’s birthday falls on 21^{st} May.

** Example:** Which two months in a year have the same calendar?

- June, October
- April, November
- April, July
- October, December
- None of these

** Answer: **Two months will have the same calendar if the period between them is divisible by 7. Now,

- June + July + Aug. + Sep.

= 30 + 31 + 31 + 30

= 122 (not divisible by 7)

- Apr. + May + June + July + Aug. + Sep. + Oct.

= 30 + 31 + 30 + 31 + 31 + 30 + 31

= 213 (not divisible by 7)

- Apr. + May + June = 30 + 31 + 30

= 91 (divisible by 7)

- October + November = 31 + 30

= 61 (not divisible by 7)

So, the correct answer is (c).